3[3-(2-9x)]+x=4(7x+2)-5

Solution for 3[3-(2-9x)]+x=4(7x+2)-5 equation:

Simplifying
3[3 + -1(2 + -9x)] + x = 4(7x + 2) + -5
3[3 + (2 * -1 + -9x * -1)] + x = 4(7x + 2) + -5
3[3 + (-2 + 9x)] + x = 4(7x + 2) + -5

Combine like terms: 3 + -2 = 1
3[1 + 9x] + x = 4(7x + 2) + -5
[1 * 3 + 9x * 3] + x = 4(7x + 2) + -5
[3 + 27x] + x = 4(7x + 2) + -5

Combine like terms: 27x + x = 28x
3 + 28x = 4(7x + 2) + -5

Reorder the terms:
3 + 28x = 4(2 + 7x) + -5
3 + 28x = (2 * 4 + 7x * 4) + -5
3 + 28x = (8 + 28x) + -5

Reorder the terms:
3 + 28x = 8 + -5 + 28x

Combine like terms: 8 + -5 = 3
3 + 28x = 3 + 28x

Add '-3' to each side of the equation.
3 + -3 + 28x = 3 + -3 + 28x

Combine like terms: 3 + -3 = 0
0 + 28x = 3 + -3 + 28x
28x = 3 + -3 + 28x

Combine like terms: 3 + -3 = 0
28x = 0 + 28x
28x = 28x

Add '-28x' to each side of the equation.
28x + -28x = 28x + -28x

Combine like terms: 28x + -28x = 0
0 = 28x + -28x

Combine like terms: 28x + -28x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.